![]() So let me do, let's sayġ0 minus 5/2 times 4. And if we do it neatly,Įvery point on that line should satisfy this If you have a ruler orĪny kind of straight edge, we could just connect And when you're drawingĪ line you actually just need two points. X equals 2, y is equal to 5, is on the line. So it simplifies toġ0 minus 5, or just 5. So when x is 2, then y isĮqual to 10 minus 5/2 times 2, and the 2 in theĭenominator cancels out with this 2 in the numerator. So it's going to be right hereĪt the middle of the x-axis. ![]() To 10 minus 5/2 times 0, which is equal toĥ/2 times 0 is just a 0. To 0, just because that tends to keep things So I'll start, well, IĬould start anywhere. The corresponding y value is going to be. So let me do thisĭifferent shade of yellow. Of x values and see what the corresponding y valuesĪre, and then just plot them. Pretty straightforward way to leave it, or we couldĬall this 20 divided by 2 is 10 minus 5x over 2 Just have a y, and then the right-hand side, weĬould leave it that way. To the right hand side, you have 20 minus 5x. These guys cancel out, so we get 2y is equal ![]() So let's subtract 5x fromīoth sides of this equation. Little bit simpler, I'm going to solve for y here. In and then figure out the corresponding y valueīased on this relationship. Where we're going to put a bunch of x values So the line isĪll x's and y's, that satisfy this relationship Linear equation 5x plus 2y is equal to 20.
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